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Re: [xsl] xpath-default-namespace with a variable

2011-09-19 08:21:47
On 19 September 2011 14:06, Murray McDonald 
<m(_dot_)mcdonald(_at_)cogeco(_dot_)ca> wrote:
I am using XSLT 2 via AltovaXML.

I have a need to look up "key" terms in an external glossary document.  The
external document has a default namespace at the root level.  The code works
fine like this:

<xsl:param name="GLOSSARY" select="'./working_files/glossary.xml'"/>

<xsl:key name="definitions" match="glossentry" use="term/@key"
xpath-default-namespace="http://www.abcdef.com/hij"/>

<xsl:variable name="glossaryDocument" select="document($GLOSSARY)"/>

...

<xsl:variable name="definition">
       <xsl:for-each select="$glossaryDocument">
               <xsl:value-of select="key('definitions',
$normalizedText)/definition" xpath-default-namespace="
http://www.abcdef.com/hij"/>
       </xsl:for-each>
</xsl:variable>

After testing I decided to replace the "hardcoded" namespace with a "global"
variable.  I was surprised to find that this did not work.

<xsl:variable name="glossNS" select="'http://www.abcdef.com/hij'"
as="xs:anyURL"/>

<xsl:key name="definitions" match="glossentry" use="term/@key"
xpath-default-namespace="{$glossNS}"/>

...

               <xsl:value-of select="key('definitions',
$normalizedText)/definition" xpath-default-namespace="{$glossNS}"/>

I've check the spec and I can't find anything to make me believe this
shouldn't work but it's entirely possible I may have missed some subtlety.

You can't declare namespaces using AVTs.... I would just declare the
namespace with a prefix once on your root element and then use that in
the key definition:

<xsl:stylesheet ... xmlns:foo="http://www.abcdef.com/hij";>

<xsl:key name="definitions" match="foo:glossentry" use="term/@key"/>



-- 
Andrew Welch
http://andrewjwelch.com

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