At 2011-10-23 17:10 -0700, Mark wrote:
Although they do have the virtue of giving me my desired output, can
the following sequence of statements be replaced by a more
generalized (shorter and simpler) XPath statement without the
repetitive "when" tests shown below?
<xsl:choose>
<xsl:when test="@souvenir-sheet">
<xsl:copy-of select="if (../Location/@souvenir-sheet)
then ../Location/@souvenir-sheet else if
(../Location/@denomination) then ../Location/@denomination else '0' "/>
</xsl:when>
<xsl:when test="@minisheet">
<xsl:copy-of select="if(../Location/@minisheet) then
../Location/@minisheet else if(../Location/@denomination) then
../Location/@denomination else '0'"/>
</xsl:when>
<xsl:when test="@booklet">
<xsl:copy-of select="if(../Location/@booklet) then
../Location/@booklet else if(../Location/@denomination) then
../Location/@denomination else '0'"/>
</xsl:when>
<xsl:when test="@se-tenant">
<xsl:copy-of select="if (../Location/@se-tenant) then
../Location/@se-tenant else if(../Location/@denomination) then
../Location/@denomination else '0'"/>
</xsl:when>
<xsl:when test="@coupon">
<xsl:copy-of select=" if (../Location/@coupon) then
../Location/@coupon else if(../Location/@denomination) then
../Location/@denomination else '0'"/>
</xsl:when>
</xsl:choose>
My XPath is very weak.
I tried:
<xsl:copy-of select="if (../Location[name(@*)=name(@*)]) then
../Location/@* else if(../Location/@denomination) then
../Location/@denomination else '0'"></xsl:copy-of>
Presuming you have only a single attribute (the name() function will
abend if you have more than one), this may work for you ... it
expresses a sequence and selects the first member of that sequence:
<xsl:copy select="( ../Location[name(@*)=name(current()/@*)] ,
../Location/@denomination ,
'0' )[1]"/>
This relies on the XPath 2 behaviour of sequence ( (), x ) collapsing to ( x ).
Note the use of current() to return the node that was current at the
start of evaluating the XPath expression (also available in XPath 1).
I hope this helps.
. . . . . . . . . Ken
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