[xsl] Children with the same name

Hi

I'm stuck with an Xpath. How can I select child nodes with the same name? The 
names are arbitrary. So far I have this, which does not work:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

  <xsl:output method="xml" encoding="utf-8" indent="yes"/>

  <xsl:template match="/">
    <test>
      <xsl:apply-templates select="array/node()[name() = name(../node())]" />
    </test>
  </xsl:template>

  <xsl:template match="node()">
    <xsl:copy-of select="*" />
  </xsl:template>

</xsl:stylesheet>

Input

<array>
  <item/>
  <nope/>
  <item>4</item>
  <item>5</item>
  <wibble/>
  <item>six</item>
  <wibble>stuff</wibble>
  <item>item</item>
  <no/>
</array>

Desired output

<array>
  <item>4</item>
  <item>5</item>
  <wibble/>
  <item>six</item>
  <wibble>stuff</wibble>
  <item>item</item>
</array>


Thanks

-----Original Message-----
From: Merrilees, David
Sent: 18 October 2011 16:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] required parameter

It returns

<form id="fLanguage" action="/en-GB/Language/Set" method="post"></form>

Thanks

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