I've been looking at the xsl functions for some way of gaining the base
output uri, or better still, the output document name. I can find how to get
the input document, the static context, but not the output document name.
I'm using Saxon with the -o parameter, so I could add an extra parameter to
my stylesheet such as "outputURI=x", but that would seem messy.
I'm sure it's really obvious, but I've not found anything yet.
It's because 'normally' the stylesheet isn't responsible for writing
the output to disk, the xsl:output values are only hints to the
processor... so there isn't a way to discover the output filepath.
You can however take control of the serialisation yourself within the
transform by using xsl:result-document, something like:
<xsl:template match="/">
<xsl:result-document href="$some-path">
...
that way you know the output path.
--
Andrew Welch
http://andrewjwelch.com
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