Gian Paolo Bernardini wrote:
<Class code="B">
<SubClass code="b1"/>
<SubClass code="b2"/>
<Rubric kind="preferred">
<Label xml:lang="it">FUNZIONI CORPOREE</Label>
<Label xml:lang="en">BODY FUNCTIONS</Label>
</Rubric>
<Rubric kind="definition">
<Label xml:lang="it">Le funzioni corporee sono
..</Label>
<Label xml:lang="en">Body functions ...</Label>
</Rubric>
</Class>
The aim is the same, now it must be chosen the text inside the<Label
xml:lang="it"> inside<Rubric kind="preferred"> since there are more kind
attributes for<Rubric> element.
<xsl:template match="Class" mode="path">
<xsl:variable name="next" select="key('k1', SuperClass/@code)"/>
<xsl:if test="$next">
<xsl:apply-templates select="$next" mode="path"/>
<xsl:text>/</xsl:text>
</xsl:if>
<xsl:value-of select="concat(@code,' ', Rubric)"/>
</xsl:template>
You just need to change the
<xsl:value-of select="concat(@code,' ', Rubric)"/>
to
<xsl:value-of select="concat(@code,' ', Rubric[@kind =
'preferred']/Label[lang('it')])"/>
--
Martin Honnen --- MVP Data Platform Development
http://msmvps.com/blogs/martin_honnen/
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