Hi Roelof,
This time, I'm not late !
I don't see any difficulty to get the HTML ouput, it's just in the same
order than the XML. I would actually
- match the root "menu" element to make the html, head and body elements,
- then match "section" to make the "div id=firstpane" (be carefull with
id unicity if the xml contains many sections) and his skeleton i.e
"menu_head" and "menu_body"
- then match "year" to fullfill menu_head
- then "month" to construct the links
- and ignoring entry
But maybe the problem is about converting numerical month values to
litterals ones ?
To do this, you have to write somewhere the correspondance "numeric -
litteral".
You have 2 options :
- either in an external xml file (i think this kind of file is call
"authority list")
=> then reading the file from your XSL (using document() function,
or aggregate it before with xproc/cocoon... many solutions here)
- or within your XSLT :
- with a test (choose/when/otherwise..) but this is not handy to
maintain
- with variable
- type nodeset if XSLT1
- containing a sequence (XSLT2)
Hope this help,
Matthieu
Le 05/01/2012 11:33, Roelof Wobben a écrit :
Hello,
Last question and then I have the site ready.
I have now this xml :
<menu>
<section id="9" handle="dagboek">Dagboek</section>
<year value="2005">
<month value="03">
<entry id="17" />
</month>
<month value="02">
<entry id="16" />
<entry id="15" />
<entry id="14" />
</month>
</year>
</menu>
And I like to have this output :
<div id="firstpane" class="menu_list">
<p class="menu_head">2005</p>
<div class="menu_body">
<a href="#">februari</a>
<a href="#">maart</a>
</div>
</div>
And I wonder now what's the best approach to get all the months under the year ?
Regards,
Roelof
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NeoLibris
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