Hi.
I am currently trying to transform the xml as shown below. It requires
me to essentially find the distinct list of all people who have the same
set of meeting dates and times, and then group them by those that have
the same dates and times together.
i.e. a single invitee is never split over multiple appointment groups -
if they have all days the same and one extra, then they become a new group.
<Appointments>
<Appointment Date="2011-01-01" TimeOfDay="06:00:00"
AppointmentType="Meeting">
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Appointment>
<Appointment Date="2011-01-02" TimeOfDay="06:00:00"
AppointmentType="Meeting">
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
<Invitee Firstname="Gordon" Surname="Jones"/>
</Appointment>
<Appointment Date="2011-01-03" TimeOfDay="06:00:00"
AppointmentType="Meeting">
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
<Invitee Firstname="Gordon" Surname="Jones"/>
</Appointment>
<Appointment Date="2011-01-02" TimeOfDay="06:00:00"
AppointmentType="PhoneHookup">
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Appointment>
</Appointments>
Into:
<MeetingPlan>
<Appointments TimeOfDay="06:00:00" AppointmentType="Meeting">
<Dates>
<MeetingDate date="2011-01-01"/>
<MeetingDate date="2011-01-02"/>
<MeetingDate date="2011-01-03"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="Meeting">
<Dates>
<MeetingDate date="2011-01-02"/>
<MeetingDate date="2011-01-03"/>
</Dates>
<Invitees>
<Invitee Firstname="Gordon" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="PhoneHookup">
<Dates>
<MeetingDate date="2011-01-02"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
</MeetingPlan>
I've had some success thus far. The following transform:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/xpath-functions";
xmlns:xd="http://www.oxygenxml.com/ns/doc/xsl";
exclude-result-prefixes="xd xs fn" version="2.0">
<xd:doc scope="stylesheet">
<xd:desc>
<xd:p><xd:b>Created on:</xd:b> Feb 1, 2 amarendy</xd:p>
<xd:p><xd:b>Author:</xd:b>Anthony Marendy</xd:p>
</xd:desc>
</xd:doc>
<xsl:template match="//Appointments">
<MeetingPlan>
<xsl:for-each-group select="//Invitee"
group-by="../@AppointmentType">
<xsl:variable name="currentAppointmentType"
select="current-grouping-key()"/>
<xsl:for-each-group select="current-group()"
group-by="../@TimeOfDay">
<xsl:variable name="currentTimeOfDay"
select="current-grouping-key()"/>
<xsl:variable
name="appointmentsWithSameTypeAndTime" select="current-group()"/>
<xsl:for-each-group
select="$appointmentsWithSameTypeAndTime" group-by="@Surname">
<xsl:variable name="currentSurname"
select="current-grouping-key()"/>
<xsl:for-each-group select="current-group()"
group-by="@Firstname">
<xsl:variable name="currentFirstname"
select="current-grouping-key()"/>
<!-- Get the list of appointments that the
current invitee has. -->
<xsl:variable name="inviteeAppointments"
select="for $d in current-group()/.. return $d"/>
<xsl:if test="(count($inviteeAppointments)
> 0)">
<Appointments
TimeOfDay="{$currentTimeOfDay}" AppointmentType="{$currentAppointmentType}">
<Dates>
<xsl:for-each
select="$inviteeAppointments">
<MeetingDate date="{./@Date}"/>
</xsl:for-each>
</Dates>
<Invitees>
<!-- Now loop through and find
all invitees that have the same combination of appointments -->
<xsl:for-each-group
select="$appointmentsWithSameTypeAndTime" group-by="@Surname">
<xsl:variable
name="loopSurname" select="current-grouping-key()"/>
<xsl:for-each-group
select="current-group()" group-by="@Firstname">
<xsl:variable
name="loopFirstname" select="current-grouping-key()"/>
<xsl:variable
name="entriesForCurrentInvitee" select="current-group()"/>
<xsl:variable
name="loopAppointments" select="for $d in $entriesForCurrentInvitee/..
return $d"/>
<xsl:if
test="fn:deep-equal($loopAppointments, $inviteeAppointments)">
<Invitee
Firstname="{$loopFirstname}" Surname="{$loopSurname}"/>
</xsl:if>
</xsl:for-each-group>
</xsl:for-each-group>
</Invitees>
</Appointments>
</xsl:if>
</xsl:for-each-group>
</xsl:for-each-group>
</xsl:for-each-group>
</xsl:for-each-group>
</MeetingPlan>
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Produces the following output:
<?xml version="1.0" encoding="UTF-8"?>
<MeetingPlan>
<Appointments TimeOfDay="06:00:00" AppointmentType="Meeting">
<Dates>
<MeetingDate date="2011-01-01"/>
<MeetingDate date="2011-01-02"/>
<MeetingDate date="2011-01-03"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="Meeting">
<Dates>
<MeetingDate date="2011-01-01"/>
<MeetingDate date="2011-01-02"/>
<MeetingDate date="2011-01-03"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="Meeting">
<Dates>
<MeetingDate date="2011-01-02"/>
<MeetingDate date="2011-01-03"/>
</Dates>
<Invitees>
<Invitee Firstname="Gordon" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="PhoneHookup">
<Dates>
<MeetingDate date="2011-01-02"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
<Appointments TimeOfDay="06:00:00" AppointmentType="PhoneHookup">
<Dates>
<MeetingDate date="2011-01-02"/>
</Dates>
<Invitees>
<Invitee Firstname="Martha" Surname="Jones"/>
<Invitee Firstname="Louis" Surname="Jones"/>
</Invitees>
</Appointments>
</MeetingPlan>
The way the transform works is that it works its way down find a
particular appointment type and time, then it determines the list of
dates for that appointment. It then loops through all of the
appointments of that type and time to find any that have the same set of
dates.
You can see that the output the problem is that the output is
duplicated. The reason is that that there are multiple appointments in
the same set, and each of these will match in the second lookup.
Firstly, I just can't help but feeling I'm going about this the wrong
way, so suggestions to other approaches would be appreciated.
Alternately, can anyone suggest how I could remove these duplicates?
I have thought about passing the result through a second stylesheet -
which I could live with, but would prefer a different solution.
Thanks,
Anthony.
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