On 29 February 2012 11:02, <davep(_at_)dpawson(_dot_)co(_dot_)uk> wrote:
input a directory full of .xml files
running a transform to modify one element, identity
transform for the rest.
(Yes, I have created a backup)
I want to
process A.xml, write out A.xml ... somehow
(no I'm not on Linux to make it easy)
I'm using
<xsl:for-each select="collection('file:///Long-path?select=*.xml')">
<xsl:result-document
href="???"
method="xml"
encoding="utf-8"
indent="yes">
<xsl:apply-templates/>
base-uri(.) returns the full pathname of the source document?
Do I have to work with that to obtain A.xml?
(text processing....)
Is there some way I can obtain the filename.extn?
1. use Kernow :)
or
2. use tokenize(document-uri(.), '/')[last()]
--
Andrew Welch
http://andrewjwelch.com
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