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Re: [xsl] is it possible to resize an image to display smaller than the original

2012-04-02 10:13:29
Thank you.  I've not tried the scaling yet as I can't get the image to
display.  I keep getting:

Apr 2, 2012 10:05:14 AM org.apache.fop.fo.flow.ExternalGraphic bind
SEVERE: Image not available: No ImagePreloader found for

Here is the line in the xml: (which the image changes w/ every new xml).

<photo>/RPT/0000718.jpg</photo>

and here is the xsl:

<fo:external-graphic src="'url({photo})'"/>

Many thanks for the replys and my apologies as I am trying to learn
this "on the fly" unfortunately.

David







On Sun, Apr 1, 2012 at 3:09 AM, davep <davep(_at_)dpawson(_dot_)co(_dot_)uk> 
wrote:
On 31/03/12 14:39, David Ryan wrote:

I changed the xsl to use your suggestion:

 <fo:external-graphic src="file:{/data/Photo}"/>

but when I run it, it doesn't find the image file saying Image not
available.  I confirmed the image is in the referenced location.  any
ideas?


http://www.w3.org/TR/xsl/#fo_external-graphic

try
<fo:external-graphic src="url(file.jpg)" />
If you can, make the file relative rather than absolute and
don't have spaces in path or filenames.


Two attributes useful for scaling are
content-height="3" scaling="uniform"
or content-width

HTH



regards

--
Dave Pawson
XSLT XSL-FO FAQ.
http://www.dpawson.co.uk

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