Interesting, doubling the curly braces seems to do what you want:
$ echo "<foobar/>" | xsltproc curly.xsl -
<target name="clean"><delete dir="${basedir}/target"/></target>
$
$ cat curly.xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
<xsl:output omit-xml-declaration="yes" />
<xsl:template match="/">
<target name="clean" >
<delete dir="${{basedir}}/target" />
</target>
</xsl:template>
</xsl:stylesheet>
$
Mit besten Gruessen / Best wishes,
Hermann Stamm-Wilbrandt
Level 3 support for XML Compiler team and Fixpack team lead
WebSphere DataPower SOA Appliances
https://www.ibm.com/developerworks/mydeveloperworks/blogs/HermannSW/
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From: Mansour Al Akeel <mansour(_dot_)alakeel(_at_)gmail(_dot_)com>
To: xsl-list <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>,
Date: 04/20/2012 11:27 PM
Subject: [xsl] curly braces in attributes
I am trying to generate xml that contains attributes with with curly
braces.
My style sheet has something like:
<target name="clean" >
<delete dir="${basedir}/target" />
</target>
The results I am getting now is:
<target name="clean" >
<delete dir="$/target"/>
</target>
I am expecting the same to output the same text. I tried to use
<xsl:text> and CDATA. The only way I was able to get the output I
needed is using CDATA inside <xsl:text> for the parts,
I need to output unchanged and unescaped.
Is there a better to disable expression evaluation. Thank you.
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