Re: [xsl] use choose in call-templates not possble

I am doing this
   <xsl:variable name="Fcfactor">
      <xsl:call-template name="translateDcml">
      <xsl:choose>
      <xsl:when test="FCDecimalPlace  != ''">
      
      
       <xsl:with-param name="factor" select="FCDecimalPlace"/>
     
      <xsl:otherwise>
      <xsl:with-param name="factor" select="LCDecimalPlace"/>
        </xsl:otherwise>
        </xsl:choose>
     </xsl:call-template>
     </xsl:variable>

???

----- Ursprüngliche Message -----
Von: Liam R E Quin <liam(_at_)w3(_dot_)org>
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
CC: 
Gesendet: 14:16 Donnerstag, 10.Mai 2012
Betreff: Re: [xsl] use choose in call-templates not possble

On Thu, 2012-05-10 at 13:02 +0100, henry human wrote:
> Hello 
> I am using a xsl:choose  in call-template but  get ever the  message:
> Child element <xsl:choose> is not allowed within xsl:call-template
> How can i avod it?
> ???
Don't do it?

Without seeing what you're trying to do it's hard to guess.

Maybe you're using xsl:choose to determine which parameters to pass?? If
so, you probably need to refactor.

Liam

-- 
Liam Quin - XML Activity Lead, W3C, http://www.w3.org/People/Quin/
Pictures from old books: http://fromoldbooks.org/


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