I guess you could:
1. Run one preliminar transformation that only outputs the total number of
rows (M).
2. Run a script that calls the XSLT processor M times, passing it the
iteration number (N) as a parameter, and thus run the transformation on the row
with index N.
—
Jorge
El 17/05/2012, a las 13:50, Michael Kay escribió:
In XSLT 1.0, each transformation can only produce one result document. So you
will have to organize some kind of script that invokes the same
transformation repeatedly, supplying parameters to indicate which range of
rows you want to select on each run.
Michael Kay
Saxonica
On 17/05/2012 12:21, Siddhi Thakkar wrote:
Hi experts,
I have an xml file like this:
<Data>
<Row>
<Cell1>text 1</Cell1>
<Cell2>text 2</Cell2>
</Row>
<Row>
<Cell1>text 3</Cell1>
<Cell2>text 4</Cell2>
</Row>
<Row>.....<Row>
<Row>.....<Row>
.....
</Data>
And I have thousands of<Row> elements like this. For the first 50 rows, I
should be able to create an output xml with name Data1.xml, for next 50 rows
output xml should be data2.xml, for next 50 rows output should be data3.xml
and so on until all the rows are complete. And I have to achieve this with
XSLT 1.0. Can anybody please help?
Thanks,
Siddhi
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--