Hi ken
fine! thanks, I will try it.
k regards
hh
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Von: G. Ken Holman <gkholman(_at_)CraneSoftwrights(_dot_)com>
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CC:
Gesendet: 13:59 Freitag, 15.Juni 2012
Betreff: Re: [xsl] shortest way to write this xsl:if statement
At 2012-06-15 12:54 +0100, henry human wrote:
Hello
The following if statement is too long if try it as in the sample bellow.
How could be shorter?
The if - logic to create a for-each loop:
----------------
xsl:if
D4/G100/6id or D4/G100/9id or D4/G100/12id or D4/G100/6id15 or D4/G100/45id
or D4/G100/22id, D4/G100/10id
or D4/G100/19id is 'A' or 'B' or 'C', or 'D' or 'F'
The Sample:
<xsl:if test="D4/G100/6id = 'A' OR test="D4/G100/6id = 'B' OR
test="D4/G100/6id = 'C' OR test="D4/G100/9id = 'A' OR test="D4/G100/9id = 'B'
.....>
<xsl:for-each select=" ......">
...
</xsl:for-each>
</xsl:if>
Element names cannot begin with digits, so I'm unclear how you are going to be
testing elements such as <6id>.
But, assuming you had elements D4/G100/X and D4/G100/Y and D4/G100/Z, you could
have in XSLT2 the following:
<xsl:if test="D4/G100/(X,Y,Z) = ('A','B','C')">
... which is equivalent to:
D4/G100/X = 'A' or
D4/G100/X = 'B' or
D4/G100/X = 'C' or
D4/G100/Y = 'A' or
D4/G100/Y = 'B' or
D4/G100/Y = 'C' or
D4/G100/Z = 'A' or
D4/G100/Z = 'B' or
D4/G100/Z = 'C'
When using the "=" comparison operator, either operand can be a set. The
processor walks through the comparisons in an arbitrary order eventually
testing each of the left operand with each of the right operand and stops when
it hits a true() result and returns true(). If you get a false() returned, you
know the processor has checked every possible combination and every combination
has returned false().
I hope this helps.
. . . . . . . . . . . Ken
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