[xsl] How to make this XSL transformation consider only for siblings wit

Hello,
I have this input in XML:

<myroot>
    <nodeA id="a">
        <section id="i">
            <item1 id="1" method="create">
                <otherchild>a</otherchild>
            </item1>
        </section>

        <section id="ii">
        <item1 id="1" method="stop">
                <otherchild>a</otherchild>
            </item1>
            <item1 id="1" method="create">
                <otherchild>a</otherchild>
            </item1>
        </section>

        <section id="i">
            <item1 id="1" method="create">
                <otherchild>a</otherchild>
            </item1>
        </section>
    </nodeA>
</myroot>

and the expected Output is:
<myroot>
    <nodeA id="a">
        <section id="i">
            <item1 id="1" method="create">
                <otherchild>a</otherchild>
            </item1>
        </section>

        <section id="ii">
            <item1 id="1" method="stop">
                <otherchild>a</otherchild>
            </item1>
            <item1 id="1" method="create">
                <otherchild>a</otherchild>
            </item1>
        </section>

        <section id="i"/>
    </nodeA>
</myroot>


I have this XSLT 2.0 :

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:output indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="*[*]
         [deep-equal(.,
           preceding::*[name()=current()/name()]
                       [@id = current()/@id]
                       [../../@id = current()/../../@id]
                       [1])]" />
</xsl:stylesheet>

I need to remove successive duplicate node. And right now the xslt is
taking all the siblings (section) although it has different id.

How to fix the xslt 2.0 to consider only sibling (section) with the
same id only?

Thanks very much.
Jo

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