Here is my code.
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/xpath-functions";
xmlns:tn="http://";
exclude-result-prefixes="xsl xs fn tn">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="genre/*">
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:apply-templates select="
book[@id=current()/@id][@action='extend']
[not( preceding-sibling::book[@id=current()/@id][@action='borrow'])]"
/>
<xsl:for-each-group
select="book[@id=current()/@id][@action='borrow']
|
book[@id=current()/@id][@action='extend']
[preceding-sibling::book[@id=current()/@id][@action='borrow']]"
group-starting-with="book[@action='borrow']">
<xsl:for-each select="current-group()[1]">
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:call-template name="merge-books-deeply">
<xsl:with-param name="books"
select="current-group()" />
<xsl:with-param name="name-path" select="()" />
</xsl:call-template>
</xsl:copy>
</xsl:for-each>
</xsl:for-each-group>
<xsl:apply-templates select="
node()[ not(
self::book[@id=current()/@id][@action=('borrow','extend')])]" />
</xsl:copy>
</xsl:template>
<xsl:function name="tn:children-on-path" as="element()*">
<xsl:param name="base" as="element()*" />
<xsl:param name="path" as="xs:string*" />
<xsl:choose>
<xsl:when test="fn:empty($base)">
<xsl:sequence select="()" />
</xsl:when>
<xsl:when test="fn:empty($path)">
<xsl:copy-of select="$base/*" />
</xsl:when>
<xsl:otherwise>
<xsl:sequence select="tn:children-on-path(
$base/*[name()=$path[1]],
$path[position() ne 1])" />
</xsl:otherwise>
</xsl:choose>
</xsl:function>
<xsl:template name="merge-books-deeply">
<xsl:param name="books" as="element()*" />
<xsl:param name="name-path" as="xs:string*" />
<xsl:for-each-group
select="tn:children-on-path($books,$name-path)"
group-by="name()">
<xsl:for-each select="current-group()[last()]" >
<xsl:copy>
<xsl:apply-templates select="@*" />
<xsl:call-template name="merge-books-deeply">
<xsl:with-param name="books" select="$books" />
<xsl:with-param name="name-path"
select="$name-path,name()" />
</xsl:call-template>
<xsl:apply-templates select="text()" />
</xsl:copy>
</xsl:for-each>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
The problem is that if i change all the book id to '1a' the code wont
work, could you point me to the right direction?
Thanks
On Tue, Jul 17, 2012 at 2:42 PM, Michel Hendriksen
<michel(_dot_)hendriksen(_at_)42(_dot_)nl> wrote:
Can;'t you try first?
On Mon, Jul 16, 2012 at 6:54 PM, Lucent Lau
<lucent(_dot_)lau(_at_)gmail(_dot_)com> wrote:
I have this XSL:
<root>
<library id="L1">
<floor1 id="1">
<shelf id="1">
<book id="1" action="borrow">
<attributes>
<user>John</user>
</attributes>
<other1>y</other1>
</book>
<book id="1" action="extend">
<attributes>
<user>Woo</user>
<length>3</length>
</attributes>
<other2>y</other2>
</book>
<book id="2" action="extend">
<attributes>
<length>2</length>
<condition>ok</condition>
</attributes>
<other3>y</other3>
</book>
</shelf>
<shelf id="2">
</floor1>
<floor1 id="2">..</floor1>
</library>
</root>
Output:
<root>
<library id="L1">
<floor1 id="1">
<shelf id="1">
<book id="1" action="borrow">
<attributes>
<user>Woo</user>
<length>3</length>
</attributes>
<other1>y</other1>
<other2>y</other2>
</book>
<book id="2" action="extend">
<attributes>
<length>2</length>
<condition>ok</condition>
</attributes>
<other3>y</other3>
</book>
</shelf>
<shelf id="2">
</floor1>
<floor1 id="2">..</floor1>
</library>
</root>
I need to combine the node such that For every node that has the same
id with action=borrow followed by one or more node with action=extend
Merge it together to the node with action=borrow.
Merge the attributes children together such that it will have all
the unique attributes from the siblings with the latest value.
leave other children unchanged
Please let me know how to fix this transformation using XSLT 2.0 ?
Thanks very much.
LL
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