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Re: [xsl] How to take a QName value and make it an attribute?

2012-08-01 10:42:38
On 1 August 2012 16:24, Costello, Roger L. <costello(_at_)mitre(_dot_)org> 
wrote:
Hi Folks,

I want to transform the <fault> element in this document:

<Test xmlns:soap="http://www.soap.org";>
    <fault>soap:client</fault>
</Test>

Note that the value of the <fault> element is

    soap:client

which is a QName.

I want to transform the <fault> element to this:

    <fault soap:client="blah">soap:client</fault>

That is, make the QName value an attribute and assign it the string "blah."

After transformation the XML document is to be this:

<Test xmlns:soap="http://www.soap.org";>
    <fault soap:client="blah">soap:client</fault>
</Test>

I tried this code:

    <xsl:template match="fault">
        <xsl:copy>
            <xsl:variable name="QName" select="." />
            <xsl:attribute name="{$QName}">blah</xsl:attribute>
            <xsl:value-of select="." />
        </xsl:copy>
    </xsl:template>

But it produces this error message:

    Undeclared prefix in attribute name: soap

What is the proper way to accomplish the desired transformation please?

You can:

- declare the soap namespace on your stylesheet element and your code
will work as it is

or

- add the 'namespace' attribute to xsl:attribute and hard code the
soap namespace in there

or

- add the 'namespace' attribute to xsl:attribute and get the soap
namespace from the source using the various namespace related
functions


-- 
Andrew Welch
http://andrewjwelch.com

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