Thanks for all the suggestions. I succeeded by using an EXSL extension
function. I am writing code for PHP, so I have to use what PHP supports. Here
is my toy code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:exsl="http://exslt.org/common"; extension-element-prefixes="exsl"
version="1.0">
<xsl:output method="xml"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="sorted">
<xsl:for-each select="/response/data/result">
<xsl:sort select="COMPANY_SORT" data-type="text" order="descending"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="/response/data/result">
<xsl:variable name="position" select="position()"/>
<xsl:copy-of select="exsl:node-set($sorted)/*[$position]"/>
</xsl:template>
</xsl:stylesheet>
On Oct 19, 2012, at 1:03 PM, Darren Oh wrote:
I am trying to generate a stylesheet that copies an XML source document. The
only change should be that nodes selected by an XPath expression are sorted.
I want this to work for any XML source document. The only information
available to generate the stylesheet is the XPath expression and the sort
criteria. I think this requires creating a template for the parents of the
nodes selected by the XPath expression. How can I do this?
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