If the xmlns="" appears on the outermost element then the XDM data model
is indistinguishable from one in which the xmlns="" is absent - so the
XSLT processor doesn't know it's there.
If it appears elsewhere the question gets terribly complicated: see
https://www.w3.org/Bugs/Public/show_bug.cgi?id=5857
Michael Kay
Saxonica
On 17/11/2012 13:39, Costello, Roger L. wrote:
Hi Folks,
I want to do an identity transform of this:
----------------------------------------------------------------------------
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.bar.com"
xmlns:bar="http://www.bar.com"
xmlns=""
elementFormDefault="qualified">
...
</xs:schema>
----------------------------------------------------------------------------
Notice the default namespace declaration, xmlns=""
Here is the code that I use to do the identity transform:
<xsl:template match="xs:schema">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:sequence select="node() | comment() | processing-instruction()"
/>
</xsl:copy>
</xsl:template>
(I use this code because I actually do more than just an identity transform,
which I do not show here.)
Here is the output from transforming the <xs:schema> with my code:
----------------------------------------------------------------------------
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.bar.com"
xmlns:bar="http://www.bar.com"
elementFormDefault="qualified">
...
</xs:schema>
----------------------------------------------------------------------------
Yikes!
What happened to the default namespace declaration?
Questions:
1. Why is my code not copying over the default namespace declaration?
2. What change can I make to my code to ensure that it copies over the default
namespace declaration?
/Roger
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