At 2013-05-13 02:49 +0100, Ihe Onwuka wrote:
I understand but what I described is what I want to do - no it is not
an academic exercise.
See an example of the required grouping - attribute and text nodes may
be present but are ignored for the purpose of grouping.
<A>
<!-- start group>
<B>
<C>
<D>
</B>
<B>
<C>
<D>
</B>
<! --end group>
<B> *** singleton group
<C> *** singleton group
<!-- start group>
<D>
<E>
<E>
<F>
<E>
</D>
<D>
<E>
<E>
<F>
<E>
</D>
<!-- end group>
<!-- start group>
<B>
<C>
<D>
</B>
<B>
<C>
<D>
</B>
<! --end group>
</A>
Okay ... from what I can tell your original statement:
I am trying to group the children of each
element by the local name of all of the
descendant elements of each child.
... might be better expressed as:
I am trying to group adjacent children
where the sets of local names of descendent
elements in document order of each child
are identical.
... in which case the expression (untested) might be the following
where I've taken the set of local names and created a singleton
string value for grouping by joining them together:
select="*" group-adjacent="string-join(descendent::*/local-name(),' ')"
I hope this helps.
. . . . . . . . . Ken
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