Thank you everyone for your comments. They gave me the clue I needed.
The below code is working for my situation, which transforms an
existing XML by updating dao[@href].
<xsl:template match="dao[@href]">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates />
<xsl:attribute name="href">
<!-- do stuff -->
</xsl:attribute>
</xsl:copy>
</xsl:template>
Nathan
On Thu, Aug 15, 2013 at 11:25 AM, David Carlisle
<davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
On 15/08/2013 15:41, Nathan Tallman wrote:
I'd like to change the values of attribute "href", whenever it appears
inside a "dao" element. From what I can tell, my template is correct,
however when ever I stick anything inside xsl:attribute (replace <!--
do stuff here -->, nothing happens during the transformation. Am I
missing something?
<xsl:template match="@href[parent::dao]">
<xsl:attribute name="href">
<!-- do stuff here -->
</xsl:attribute>
</xsl:template>
I'm using XSLT 2.0, Saxon 6.5.5.
Thanks,
Nathan
In addition to the other comments re XSLT version and namespaces, a template
matching an attribute only does anything if you apply templates to that
attribute. The default processing does not do that:
<xsl:template match="dao">
... stuff..
<xsl:apply-templates/>
..
</xsl:template>
would apply templates to child nodes of <dao> but not to its attributes.
David
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