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RE: [xsl] Nested lists

2013-10-31 20:05:18
Hi Heiko,

Thanks. I am using MSXML so I have to do this with XSLT 1.0.

Rick

-----Original Message-----
From: Heiko Niemann [mailto:kontakt(_at_)heiko-niemann(_dot_)de] 
Sent: Thursday, October 31, 2013 8:13 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Nested lists

Hi,

using XSLT 2.0 this does what you want (somebody might improve this since
grouping feels still new to me):


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
  <xsl:output method="xml" encoding="UTF-8"/>
  <xsl:template match="/">
    <body>
      <xsl:for-each-group select="/body/*"
group-starting-with="*[not(@class = ('listitembullets',
'listitemindented'))]">
        <xsl:copy-of select="."/>
        <xsl:call-template name="list"/>
      </xsl:for-each-group>
    </body>
  </xsl:template>
  <xsl:template name="list">
    <xsl:if test="current-group()[2]">
      <ul>
        <xsl:variable name="cl" select="current-group()[2]/@class"/>
        <xsl:for-each-group select="current-group() except ."
group-starting-with="p[@class = $cl]">
          <li>
            <xsl:value-of select="text()"/>
            <xsl:call-template name="list"/>
          </li>
        </xsl:for-each-group>
      </ul>
    </xsl:if>
  </xsl:template>
</xsl:stylesheet>


Output:


<body>
  <p class="listintro">ListItem_Bullets:</p>
  <ul>
    <li>. Item 1</li>
    <li>. Item 2</li>
    <li>. Item 3</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
    <li>. Item 4</li>
    <li>. Item 5
      <ul>
        <li>. Item 1 indented</li>
        <li>. Item 2 indented</li>
      </ul>
    </li>
    <li>. Item 6</li>
  </ul>
  <h2>Indented list starts here:</h2>
  <ul>
    <li>. Item 1 indented</li>
    <li>. Item 2 indented</li>
    <li>. Item 3 indented</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
    <li>. Item 4 indented</li>
    <li>. Item 5 indented</li>
    <li>. Item 6 indented</li>
  </ul>
</body>


Heiko


Hi,

I have this for my input XML:

<body>
  <p class="listintro">ListItem_Bullets:</p>
  <p class="listitembullets">&#8226; Item 1</p>
  <p class="listitembullets">&#8226; Item 2</p>
  <p class="listitembullets">&#8226; Item 3</p>
  <p class="normal">Paragraph within a list.</p>
  <p class="listitembullets">&#8226; Item 4</p>
  <p class="listitembullets">&#8226; Item 5</p>
  <p class="listitemindented">&#8226; Item 1 indented</p>
  <p class="listitemindented">&#8226; Item 2 indented</p>
  <p class="listitembullets">&#8226; Item 6</p>
  <h2>Indented list starts here:</h2>
  <p class="listitemindented">&#8226; Item 1 indented</p>
  <p class="listitemindented">&#8226; Item 2 indented</p>
  <p class="listitemindented">&#8226; Item 3 indented</p>
  <p class="normal">Paragraph within a list.</p>
  <p class="listitemindented">&#8226; Item 4 indented</p>
  <p class="listitemindented">&#8226; Item 5 indented</p>
  <p class="listitemindented">&#8226; Item 6 indented</p> </body>

I want to get this:

<body>
  <p class="listintro">ListItem_Bullets:</p>
  <ul>
     <li>Item 1</li>
     <li>Item 2</li>
     <li>Item 3</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
     <li>Item 4</li>
     <li>Item 5</li>
     <ul>
       <li>Item 1 indented</li>
       <li>Item 2 indented</li>
     </ul>
     <li>Item 6</li>
  </ul>
  <h2>Indented list starts here:</h2>
  <ul>
     <li>. Item 1 indented</li>
     <li>. Item 2 indented</li>
     <li>. Item 3 indented</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
     <li>. Item 4 indented</li>
     <li>. Item 5 indented</li>
     <li>. Item 6 indented</li>
  </ul>
</body>

I am actually getting this:

<body>
  <p class="listintro">ListItem_Bullets:</p>
  <ul>
     <li>Item 1</li>
     <li>Item 2</li>
     <li>Item 3</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
     <li>Item 4</li>
     <li>Item 5</li>
  </ul>
  <h2>Indented list starts here:</h2>
  <ul>
     <li>. Item 1 indented</li>
     <li>. Item 2 indented</li>
     <li>. Item 3 indented</li>
  </ul>
  <p class="normal">Paragraph within a list.</p>
  <ul>
     <li>. Item 4 indented</li>
     <li>. Item 5 indented</li>
     <li>. Item 6 indented</li>
  </ul>
</body>

The problem is that I have some different list items represented by 
the various class attributes. I tried to get cute with keys. It works 
for all of the lists except the "listitemindented" lists. Here is my 
stylesheet. Any help will be appreciated. (Forget about the bullets; I 
can solve that
separately.)

<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
    xmlns:xhtml="http://www.w3.org/1999/xhtml";
    xmlns="http://www.w3.org/1999/xhtml";
    exclude-result-prefixes="xhtml xsl"
    version="1.0">

    <xsl:key name="orderedlists" match="xhtml:p[@class='listitem1' or 
@class='listitem2']"
use="generate-id((..|preceding-sibling::*[not(self::xhtml:p[@class='li
stitem 1' or @class='listitem2'])][1])[last()])"/>
    <xsl:key name="unorderedlists-plain"
match="xhtml:p[@class='listitemunordered']"
use="generate-id((..|preceding-sibling::*[not(self::xhtml:p[@class='li
stitem
unordered'])][1])[last()])"/>

    <xsl:key name="unorderedlists"
match="xhtml:p[@class='listitembullets']"
use="generate-id((..|preceding-sibling::*[not(self::xhtml:p[@class='li
stitem
bullets'])][1])[last()])"/>
    <xsl:key name="unorderedlists-indented"
match="xhtml:p[@class='listitemindented']"
use="generate-id((..|preceding-sibling::*[not(self::xhtml:p[@class='li
stitem
indented'])][1])[last()])"/>

    <xsl:output indent="yes"/>

    <!--this is a construct whose children need to be grouped in 
separate
lists-->
    <xsl:template match="xhtml:body">
        <body>
            <xsl:apply-templates mode="group"
select=".|*[not(self::xhtml:p[@class='listitem1' or @class='listitem2' 
or @class='listitemunordered' or @class='listitembullets' or 
@class='listitemindented'])]"/>
        </body>
    </xsl:template>

    <xsl:template mode="group" match="*">
        <xsl:apply-templates select="self::*[not(self::xhtml:body)]"/>
        <xsl:if test="key('orderedlists',generate-id(.))">
            <ol
start="{substring-before(following-sibling::*/node(),'.')}">
                <xsl:apply-templates
select="key('orderedlists',generate-id(.))"/>
            </ol>
        </xsl:if>
        <xsl:if test="key('unorderedlists-plain',generate-id(.))">
            <dl>
                <xsl:apply-templates
select="key('unorderedlists-plain',generate-id(.))"/>
            </dl>
        </xsl:if>
        <xsl:if test="key('unorderedlists-indented',generate-id(.))">
            <ul>
                <xsl:apply-templates
select="key('unorderedlists-indented',generate-id(.))"/>
            </ul>
        </xsl:if>
        <xsl:if test="key('unorderedlists',generate-id(.))">
            <ul>
                <xsl:apply-templates
select="key('unorderedlists',generate-id(.))"/>
            </ul>
        </xsl:if>
    </xsl:template>

    <!--the following template rules need no knowledge of grouping-->

    <xsl:template match="xhtml:p[@class='listitem1' or 
@class='listitem2']">
        <li><xsl:apply-templates/></li>
    </xsl:template>

    <xsl:template match="xhtml:p[@class='listitem1' or 
@class='listitem2']/text()[1]">
        <xsl:value-of select="substring-after(.,'. ')"/>
    </xsl:template>

    <xsl:template match="xhtml:p[@class='listitembullets' or 
@class='listitemindented']">
        <li><xsl:apply-templates/></li>
    </xsl:template>

    <xsl:template match="xhtml:p[@class='listitemunordered']">
        <dd><xsl:apply-templates/></dd>
    </xsl:template>

    <xsl:template match="xhtml:p[@class='listitembullets']/text()[1]">
        <xsl:value-of select="substring-after(.,'&#8226; ')"/>
    </xsl:template>

    <!-- IdentityTransform -->
    <xsl:template match="/ | @* | node()" name="identity">
        <xsl:copy><xsl:apply-templates select="@* | node()" /></xsl:copy>
    </xsl:template>

</xsl:stylesheet>


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