Rick,
Here is another way to look at the problem which identifies the first potential
list item and uses that to start an ordered list. The call-template works it
way forward outputting list items that have the same class value. I did not go
further to see how to use this for the sub lists.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheetxmlns:xsl="http://www.w3.org/1999/XSL/Transform"version="1.0";
xmlns:xhtml="http://www.w3.org/1999/xhtml";>
<xsl:outputindent="yes"/>
<xsl:strip-spaceelements="*"/>
<!-- turn off defaults -->
<xsl:templatematch="*|@*"/>
<!-- main start -->
<xsl:templatematch="/">
<xsl:apply-templates/>
</xsl:template>
<!-- push through all elements except p with a list class -->
<xsl:templatematch="xhtml:html | xhtml:head | xhtml:body | xhtml:p | xhtml:h2">
<xsl:elementname="{local-name()}">
<xsl:copy-ofselect="@*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<!-- this is a list item -->
<xsl:templatematch="xhtml:p[contains(@class , 'list')]">
<xsl:choose>
<!-- first list item -->
<xsl:whentest="preceding-sibling::*[1][not(contains(@class , 'list'))]">
<xsl:elementname="ol">
<xsl:call-templatename="look-forward">
<xsl:with-paramname="first"select="."/>
<xsl:with-paramname="here"select="."/>
</xsl:call-template>
</xsl:element>
</xsl:when>
<!-- not first list item -->
<xsl:otherwise/>
</xsl:choose>
</xsl:template>
<!-- that template looks forward one at a time on the p to extract and output
the list items -->
<xsl:templatename="look-forward">
<xsl:paramname="first"/>
<xsl:paramname="here"/>
<xsl:choose>
<xsl:whentest="$here/self::xhtml:p[contains(@class , 'list')] and $first/@class
= $here/@class">
<xsl:elementname="li">
<xsl:copy-ofselect="@*"/>
<xsl:apply-templatesselect="$here/node()"/>
</xsl:element>
<xsl:call-templatename="look-forward">
<xsl:with-paramname="first"select="$first"/>
<xsl:with-paramname="here"select="$here/following-sibling::*[1]"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise/>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Terry
On Friday, November 1, 2013 3:43 PM, Rick Quatro
<rick(_at_)rickquatro(_dot_)com> wrote:
Hi Michael,
Thanks for the excellent advice.
Rick
-----Original Message-----
From: Michael Müller-Hillebrand [mailto:mmh(_at_)docufy(_dot_)de]
Sent: Friday, November 01, 2013 12:37 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Nested lists
Hi Rick,
Compared to the pain using XSLT1 for a task which XSLT2 can easily handle,
the pain you have to go through if you are forced to change a nice working
XSLT2 solution down to XSLT1 is a real PITA.
But anyhow, I know that sometimes we are forced to do ugly stuff. I would
not be trying to use xsl:key for that problem, as keys are more of an index
across a full document and in your situation everything depends on the order
of elements. In XSLT2 you would use xsl:for-each-group, which in XSLT1
sometimes can be kind-of replicated by "tree walking"
<http://www.dpawson.co.uk/xsl/sect2/N4486.html#d5510e1105>.
As in your example the same class attribute value maybe used for a level 1
or level 2 list item, it might also be a good idea to do some preprocessing,
because otherwise some XPaths may become really long. I guess I would try to
separate the logic of finding the correct list item level from the step of
adding the required <ul>.
Good luck,
- Michael
Am 31.10.2013 um 21:22 schrieb Rick Quatro <rick(_at_)rickquatro(_dot_)com>:
Hi,
I have this for my input XML:
<body>
<p class="listintro">ListItem_Bullets:</p>
<p class="listitembullets">• Item 1</p> <p
class="listitembullets">• Item 2</p> <p
class="listitembullets">• Item 3</p> <p
class="normal">Paragraph within a list.</p> <p
class="listitembullets">• Item 4</p> <p
class="listitembullets">• Item 5</p> <p
class="listitemindented">• Item 1 indented</p> <p
class="listitemindented">• Item 2 indented</p> <p
class="listitembullets">• Item 6</p> <h2>Indented list starts
here:</h2> <p class="listitemindented">• Item 1 indented</p>
<p class="listitemindented">• Item 2 indented</p> <p
class="listitemindented">• Item 3 indented</p> <p
class="normal">Paragraph within a list.</p> <p
class="listitemindented">• Item 4 indented</p> <p
class="listitemindented">• Item 5 indented</p> <p
class="listitemindented">• Item 6 indented</p> </body>
I want to get this:
<body>
<p class="listintro">ListItem_Bullets:</p>
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
</ul>
<p class="normal">Paragraph within a list.</p> <ul>
<li>Item 4</li>
<li>Item 5</li>
<ul>
<li>Item 1 indented</li>
<li>Item 2 indented</li>
</ul>
<li>Item 6</li>
</ul>
<h2>Indented list starts here:</h2>
<ul>
<li>. Item 1 indented</li>
<li>. Item 2 indented</li>
<li>. Item 3 indented</li>
</ul>
<p class="normal">Paragraph within a list.</p> <ul>
<li>. Item 4 indented</li>
<li>. Item 5 indented</li>
<li>. Item 6 indented</li>
</ul>
</body>
--
Michael Müller-Hillebrand
mmh(_at_)docufy(_dot_)de
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