You're making it harder than it needs to be.
Just use an identity transform that has a template for <div> like:
<xsl:template match="div">
<xsl:apply-templates/>
</xsl:template>
That will filter out the <div> elements but leave their contents.
Cheers,
E.
—————
Eliot Kimber, Owner
Contrext, LLC
http://contrext.com
On 5/19/14, 3:23 PM, "Mark Peters markpeters(_dot_)work(_at_)gmail(_dot_)com"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Hi,
I'm trying to convert documentation from HTML to another markup language.
The documentation includes content nested in many various levels of
<div/> tags.
For example:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
<html xmlns="http://www.w3.org/1999/xhtml";>
<head>
<title>Title</title>
</head>
<body>
<h1>Title</h1>
<div>
<div>
<p>Text</p>
<div>
<ul>
<li>List item</li>
<li>List item</li>
<li>List item</li>
</ul>
</div>
<p>Text</p>
<h2Title</h2>
<h3>Title</h3>
<p>Text.</p>
<div>
<div>
<p>Text</p>
<div>
<div>
<div>
<div>
</body>
</html>
I simply want to remove all <div/> tags but retain the child nodes and
attributes for each. I'm also removing the <html/> nodes but retaining
the children, and removing the <head/> node altogether. But I can figure
out how to accomplish those goals.
The desired output would look like this:
<body>
<h1>Title</h1>
<p>Text</p>
<ul>
<li>List item</li>
<li>List item</li>
<li>List item</li>
</ul>
<p>Text</p>
<h2Title</h2>
<h3>Title</h3>
<p>Text.</p>
<p>Text</p>
</body>
Here's current stylesheet. I've tried to remove the <div/> tags several
different ways, using identity templates and for-each elements.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0" xmlns="http://www.w3.org/1999/xhtml";
xpath-default-namespace="http://www.w3.org/1999/xhtml";>
<xsl:output method="xml" indent="no" omit-xml-declaration="yes"
encoding="UTF-8"/>
<xsl:template match="/*">
<xsl:apply-templates select="node()"/>
</xsl:template>
<xsl:template match="head"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="body">
<xsl:element name="body">
<xsl:for-each select="//node()">
<xsl:choose>
<xsl:when test="self::div">
<xsl:apply-templates select="node()"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates
select="self::node()|node()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
With this current stylesheet, I wanted to test each child node under
<body/>. For each <div/> node, the stylesheet would copy the child nodes
and attributes only. For all other nodes, the stylesheet would copy the
current node and all children. But my output is blank.
Thanks in advance for any help.
Mark
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