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Re: [xsl] apply-templates repeats inside xsl:for-each, why

2014-06-15 20:03:50
Well, without seeing at least the code that matches <concept> and
the portion of the input that has <concept>, it's hard to impossible
to say. But my first guess would be that the code that matches
<concept id="unique_2"> generates one line of output for each
<platform>.

But a few odd things jump to mind:
 
 * It would seem there is both a <platform> and a <concept> with
   id=unique_2. While not necessarily invalid, most of us think of
   the id= attribute as an ID attribute, and thus necessarily
   unique. But even if your schema (unwisely, I daresay) permits
   values of id= to be non-unique, it seems terribly misleading to
   say in the value it self that it is unique, when it's not.

 * The predicate "[@id = @id]" will never return false, and thus
   seems a bit silly. (Perhaps you meant "[@id = $id]"? I've made
   that mistake :-)

I'm running xsl:for-each on a variable $platforms that holds this:

       <platform name="windows_xp" id="unique_2"/>
       <platform name="windows_vista" id="unique_35"/>
       <platform name="windows_7" id="unique_37"/>

The following code produces the same output 3 times for each node in 
$platforms:

         <xsl:for-each select="$platforms/platform">
           <xsl:apply-templates 
select="$root-of-input-file/map/concept/concept[@id = @id]"/>
         </xsl:for-each>

So in the output I get this kind of thing:

Windows XP
Windows Vista
Windows 7
Windows XP
Windows Vista
Windows 7
Windows XP
Windows Vista
Windows 7

I was expecting to get one output for each element in
$platforms. If I use the following outside of xsl:for-each, I get
one output:

<xsl:apply-templates select="$root/map/concept/concept[@id = 'unique_2']"/>

What am I missing?
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