Dear All,
I am using xsl:analyze-string to retrieve and replace punctuation, however, I
got the following error:
Error in regular expression: net.sf.saxon.trans.XPathException: Syntax error
at char 6 in regular expression: Escape character '!' not allowed.
How should I escape and match '?' and '!' ? I am also using a negative
look-ahead, why isn't that working?
Here is a sample from my code, thanks,
Gabor
<xsl:template match="//TEI:p//text()[ not
((parent::TEI:note)|(parent::TEI:hi)|(parent::TEI:date))]">
<xsl:analyze-string select="." regex="(\.|\!|\?)(?!\)|\.|\d|\w)">
<xsl:matching-substring>
<xsl:element name="seg"
namespace="http://www.tei-c.org/ns/1.0"><xsl:value-of select="."/></xsl:element>
</xsl:matching-substring>
<xsl:non-matching-substring>
<xsl:value-of select="."/>
</xsl:non-matching-substring>
</xsl:analyze-string>
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--