Varun,
It would be more along this:
<xsl:template match="/">
<xsl:variable name="union">
<xsl:apply-templates select="//Item" mode="step1" />
<xsl:apply-templates select="document('File2.xml')/*//Item"
mode="step1" />
</xsl:variable>
<A>
<target>
<xsl:apply-templates select="$union/*" />
</target>
</A>
</xsl:template>
with a special template for that mode "step1":
<xsl:template match="Item" mode="step1">
<xsl:copy-of select="." />
</xsl:template>
This way you would collect all <Item> in variable $union in their own, common
tree and then you can expect to have the correct context for preceding elements.
If you are on a tight timeline and the task is above your current knowledge
level you might consider seeking professional help. You should at a minimum
make yourself familiar with the concept of trees, which is required to
understand the axis.
HTH,
- Michael
Am 21.08.2014 um 11:28 schrieb varun bhatnagar varun292006(_at_)gmail(_dot_)com
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>:
Hi,
To join all the Item elements I tried using copy and copy-to elements of xsl
and then I applied the template rules but it did not work.
<xsl:template match="/">
<A>
<target>
<xsl:copy>
<xsl:apply-templates select="//Item"/>
<xsl:apply-templates select="document('File2.xml')/*//Item"/>
</xsl:copy>
</target>
</A>
</xsl:template>
Is this the correct way of doing it? Could anyone please help, I am not able
to proceed :(
Thanks,
BR,
Varun
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