Re: [xsl] Replacing an apostrophe in a string

As I have shown in my answer, tricks with swapping quotes and apostrophes
are no longer necessary.

In XPath 2.0 and up one can code ' or " by simply doubling it.


On Thu, Sep 4, 2014 at 11:58 AM, Craig Sampson 
craig(_dot_)sampson(_at_)sas(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

>  Sorry for the noise. I got it working right after posting for help.
>
>  The solution was to swap the quotes around in the statement, which I
> thought I’d already tried, but it worked this time.
>
>
>
> Eg:
>
>
>
> <xsl:variable name=”newString” select=’replace($oldString, “&apos;” ,
> “XXX”)’/>
>
>
>
> Thanks,
>
>   Craig
>    XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list>
> EasyUnsubscribe <-list/782854> (by
> email <>)


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