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[xsl] How do I properly define a unix saxon script command line

2014-11-11 15:47:10
Want to write a command line to call Saxon processor from a unix script 
line. Am using Saxon-HE from Unix command line to convert my XML file into 
a CSV file so it can be uploaded into a DB Table. We are using the DB 
table as input into our AP interface in ERP E1. Had to switch to Saxon 
processor because xsltproc does not work with xsl 2.0. 

In the command line call I need to specify two classpaths  (Classpath for 
JAVA, Classpath for SAXON jar files)

How would I call the saxon processor in a unix script and pass it the 
following information
JavaClassPath, SaxonJarClassPath, InputFile, StylesheetFile, OutputFile

So far this is the unix command line I came across on the web.  Read thru 
page 853-854 of XSLT 2.0 3rd Edition Programmer's Reference and it does 
not quite give me what I am looking for.  Where would I find all the Saxon 
command line options
Want to do saxon conversion of XML file within a unix shell script.  We 
have Java on Unix box.  Loaded Saxon jar files in a different directory on 
unix box.  Loaded stylesheet on unix box.  Loaded InputFile on unix box.

saxon –r saxonjarclasspath/saxon.jar -m javaclasspath -s:Input_File 
-xsl:Stylesheet_File  –o Output_File

_____________________________________________________________________
Catherine Wilbur  |  Senior Application Programmer  |  IT Services
401 Sunset Avenue, Windsor ON Canada  N9B 3P4
(T) 519.253.3000 Ext. 2745  |  (F) 519.973.7083  |  (E) 
cwilbur(_at_)uwindsor(_dot_)ca
www.uwindsor.ca/its
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