I think that in XSLT 1 the only solution would be to use sibling recursion:
<xsl:template name="sumcells">
<xsl:param name="inSum"/>
<xsl:variable name="sum" select="$inSum + number(.)"/>
<xsl:choose>
<xsl:when test="count(following-sibling::cell) = 0">
<xsl:value=of select="$sum"/>
</xsl:when>
<xsl:otherwise>
<xsl:for-each select="following-sibling:cell[1]">
<xsl:with-param name="inSum" select="$sum"/>
</xsl:for-each>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Cheers,
E.
—————
Eliot Kimber, Owner
Contrext, LLC
http://contrext.com
On 2/12/15, 5:42 AM, "Kevin Bird kevinbrianbird(_at_)gmail(_dot_)com"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Hello,
In <col2>, where cell = num, return the corresponding col1/cell/@value,
summing the result.
<root>
<col1>
<cell value="1">text</cell>
<cell value="12">text</cell>
<cell value="24">text</cell>
<cell value="100">text</cell>
<cell value="9">text</cell>
<cell value="6">text</cell>
</col1>
<col2>
<cell>num</cell>
<cell>-</cell>
<cell>num</cell>
<cell>-</cell>
<cell>num</cell>
<cell>num</cell>
</col2>
<col3>
<cell>-</cell>
<cell>num</cell>
<cell>num</cell>
<cell>num</cell>
<cell>num</cell>
<cell>-</cell>
</col3>
</root>
Sum for <col2> is: 40
Sum for <col3> is: 145
I'd like an XPath solution, but I don't think that is possible.
I tried using keys.
<xsl:key name="byValue" match="cell" use="/root/col1/cell[position() =
count(current()/preceding-sibling::cell)+1]/@value"/>
So each cell has the correct value, but I'm struggling to sum the values.
Maybe my thinking is wrong.
Any help appreciated.
--
Kevin
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