I did try <xsl:apply-templates select="current-group()">, thinking it would
just go through and apply the existing indexterm, primary, secondary templates
-- but I got the entire group in a chunk, it didn't seem to apply templates to
each element individually. I'll go back and look, maybe I did something wrong
there. I wasn't using mode, maybe that was the problem.
<xsl:for-each select="current-group()"> makes sense, will give that a try.
Last question: if I want to do something at the end of each group, I'd put that
instruction right before the </xsl:for-each-group>, correct?
-----Original Message-----
From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de
[mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com]
Sent: Wednesday, April 15, 2015 10:04 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Re: Sorting on two levels
Michele R Combs mrrothen(_at_)syr(_dot_)edu wrote:
The suggestion offered yesterday works great as far as the sorting, but I
need to do certain things to each item in a group as it's output, such as
wrapping each ID in an <a> element. What I tried is shown below, but it
results in @href containing *all* the ids for the group. How do I process
each item in a group separately? Do I need to at some point just do
<xsl:apply-templates select=" current-group()"> and then rely on templates
for primary, secondary, etc.? I did try that but couldn't seem to get it to
work -- either I got no output, or I got the entire group in a chunk.
<a>
<xsl:attribute name="href">
<xsl:value-of
select="current-group()/@id"/>
</xsl:attribute>
<xsl:value-of select="current-group()/@id"
separator=", "/>
If you want to map each item in a group to an HTML "a" element then use
<xsl:for-each select="current-group()">
<a href="{@id}">
<!-- not sure what you want to output for the link -->
<xsl:value-of select="@id"/>
</a>
</xsl:for-each>
or use
<xsl:apply-templates select="current-group()" mode="link"/>
and write a template
<xsl:template match="indexterm" mode="link">
<a href="{@id}">
<!-- not sure what you want to output for the link -->
<xsl:value-of select="@id"/>
</a>
</xsl:template>
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