Jorge . chocolate(_dot_)camera(_at_)gmail(_dot_)com wrote:
Having a sequence stored in a variable, how do I reference the item in
that sequence whose position is the same as the position of the
current node with respect to its context, with XSLT 2?
This does return what I expect:
<xsl:variable name="POSITION" select="position()" as="xs:integer"/>
<xsl:sequence select="$FOO[$POSITION]"/>
but I somehow feel that there must be a way to call the `position()`
of the current node from inside those brackets without the meaning of
the function actually becoming the position of the variable itself
instead of the current node's. Is there?
I don't think so, I think you need the variable.
I am using Saxon-HE 9.2.1.2J on OS X 10.10.3 (14D136).
Using the latest Saxon 9.6 and XSLT 3.0 you could delegate the variable
binding to XPath with e.g.
<xsl:sequence select="let $pos := position() return $FOO[$pos]"/>
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