Re: [xsl] Get children and text, excluding a child

The identity transform isn't just elements and attributes. (People do
sometimes get annoyed when you strip the comments from their
documents...)

<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="number[parent::span]">
    <!-- just in case there are other numbers somewhere else we don't
    want to remove -->
</xsl:template>

will do it.  If you've got a larger transformation, stick a unique mode
on both templates and it will still work so long as you use that mode
when applying templates to the spans.

-- Graydon

On Fri, Jun 12, 2015 at 10:24:43PM -0000, Ryan Graham 
ryan(_dot_)graham(_at_)apollo(_dot_)edu scripsit:

Apologies for the mangled indentation my mail client imposed. :)

On 6/12/15, 3:20 PM, "Ryan Graham ryan(_dot_)graham(_at_)apollo(_dot_)edu"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

You could also do an identity transform, omitting number elements with an
empty template match:

<xsl:template match="/">
   <xsl:apply-templates/>
    </xsl:template>
    

    <xsl:template match="@*|*">
   <xsl:copy>
       <xsl:apply-templates select="@*"/>
       <xsl:apply-templates/>
   </xsl:copy>
    </xsl:template>
    

<xsl:template match="number"/>


Thanks,
Ryan

On 6/12/15, 1:50 PM, "Rick Quatro rick(_at_)rickquatro(_dot_)com"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

I think I figured it out:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
   xmlns:xs="http://www.w3.org/2001/XMLSchema";
   exclude-result-prefixes="xs"
   version="2.0">
   
   <xsl:output method="xml" indent="yes"/>
   
   <xsl:template match="/root">
       <root>
           <xsl:for-each select="span">
               <span><xsl:copy-of
select="*[not(self::number)]|text()"/></span>
           </xsl:for-each>
       </root>
   </xsl:template>
   
</xsl:stylesheet>

-----Original Message-----
From: Rick Quatro rick(_at_)rickquatro(_dot_)com
[mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com]
Sent: Friday, June 12, 2015 4:45 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Get children and text, excluding a child

Hello,

Here is my input xml:

<?xml version="1.0"?>
<root>
 <span><number>9.3</number> <code>protected</code> members</span>
 <span><number>9.4</number> miscellaneous members.</span> </root>

Here is the desired output:

<?xml version="1.0"?>
<root>
 <span> <code>protected</code> members</span>
 <span> miscellaneous members.</span>
</root>

I want to output all of the elements and text of the original <span>
element, but without the <number> element. I am using this for my xsl:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
   xmlns:xs="http://www.w3.org/2001/XMLSchema";
   exclude-result-prefixes="xs"
   version="2.0">
   
   <xsl:output method="xml" indent="yes"/>
   
   <xsl:template match="/root">
       <root>
           <xsl:for-each select="span">
               <xsl:copy-of select="descendant::*[not(self::number)]"/>
           </xsl:for-each>
       </root>
   </xsl:template>
   
</xsl:stylesheet>

This is my current (incorrect) output:

<?xml version="1.0" encoding="UTF-8"?>
<root>
  <code>protected</code>
</root>

Any help or pointers would be appreciated. Thanks.

Rick Quatro
Carmen Publishing Inc.
585-366-4017
rick(_at_)frameexpert(_dot_)com

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