At 2016-04-07 13:40 +0000, Costello, Roger L. costello(_at_)mitre(_dot_)org
wrote:
I have a stylesheet which reads a text file and tokenizes it. The
token delimiter is two consecutive newline characters (hex 0A, hex 0A).
If I use the tokenize() function like this:
tokenize($text-file, '

')
then the text file is correctly tokenized.
But if I create an entity:
<!DOCTYPE xsl:stylesheet [
<!ENTITY line-separator '
'>
]>
and a variable whose value is two line-separators:
<xsl:variable name="rule-separator"
select="'&line-separator;&line-separator;'"/>
and then use the variable with the tokenize() function:
tokenize($text-file, $rule-separator)
then the text file is not tokenized correctly. Specifically, the
XSLT processor uses two consecutive space characters (hex 20, hex
20) as the token delimiter rather than two consecutive newline
characters (hex 0A, hex 0A) as the token delimiter.
Do you know why this is happening?
Attribute value normalization:
https://www.w3.org/TR/REC-xml/#AVNormalize
Subsection 3, bullet 1 states that a character reference is
appended.
Subsection 3, bullet 3 states that any white-space character
found in the attribute value is normalized to a space.
The numeric character reference in your first example is simply
appended. The expansion value of the entity reference in your second
example is a white-space character and so it does get normalized.
How do I fix it?
There is no way to preserve a numeric character reference in an
entity in its value:
https://www.w3.org/TR/REC-xml/#sec-references
"An entity reference refers to the *content* of a named entity."
(my emphasis)
But, you can encode the string that needs to be decoded in order to
solve your problem:
t:\>type ent.xsl
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
<!ENTITY line-separator1 '
'>
<!ENTITY line-separator2 '&#x0A;'>
]>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of select="'1=',string-to-codepoints('&line-separator1;'),
'
2=',string-to-codepoints('&line-separator2;'),
'
3=',string-to-codepoints('
')"/>
</xsl:template>
</xsl:stylesheet>
t:\>xslt2 ent.xsl ent.xsl
1= 32
2= 10
3= 10
t:\>
The content is parsed creating the sequence you need.
I hope this helps.
. . . . . . Ken
--
Check our site for free XML, XSLT, XSL-FO and UBL developer resources |
Streaming hands-on XSLT/XPath 2 training @US$45: http://goo.gl/Dd9qBK |
Crane Softwrights Ltd. _ _ _ _ _ _ http://www.CraneSoftwrights.com/s/ |
G Ken Holman _ _ _ _ _ _ _ _ _ _
mailto:gkholman(_at_)CraneSoftwrights(_dot_)com |
Google+ blog _ _ _ _ _ http://plus.google.com/+GKenHolman-Crane/posts |
Legal business disclaimers: _ _ http://www.CraneSoftwrights.com/legal |
---
This email has been checked for viruses by Avast antivirus software.
https://www.avast.com/antivirus
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--