Re: [xsl] I output a tab character, then the output file contains space,

I would use string-join for this:

<xsl:sequence select="string-join($headers,$field-separator)"/>

The for-each loop is not needed.

Someone can correct me but I believe in your code the rules for sequence
construction come into play meaning that the string result of a sequence
always includes a space between items, so you're creating a sequence of
("A", "\t", "B"), which becomes "A \t B".

Cheers,

Eliot
----
Eliot Kimber, Owner
Contrext, LLC
http://contrext.com




On 4/8/16, 11:13 AM, "Costello, Roger L. costello(_at_)mitre(_dot_)org"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

> Hi Folks,
>
> In the below XSLT program I loop over each value in a sequence and
> separate the sequence values by a tab (hex 9) character. When I open the
> output file in a hex editor I see 3 characters separating the sequence
> values: space (hex 20), tab (hex 9), and space (hex 20). Why am I getting
> those space characters? How do I avoid getting them?  /Roger
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                           version="2.0">
>    
>    <xsl:output method="text" />
>    
>    <xsl:variable name="headers" select="('A', 'B')"/>
>    <xsl:variable name="field-separator"
> select="codepoints-to-string(9)"/>
>    
>    <xsl:template match="/">
>        <xsl:for-each select="$headers">
>            <xsl:sequence select="." />
>            <xsl:sequence select="$field-separator"/>
>        </xsl:for-each>
>    </xsl:template>
>    
> </xsl:stylesheet>
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