Re: [xsl] Xslt string Operation

I meant
<xsl:variable name="OutFileName" select=" substring-before($fileHref,
tokenize($fileHref,'/')[last()] ) || $outDir || '/' ||   substring-before(
tokenize($fileHref,'/')[last()] ,'.xml') || '-Formatted.xml'"/>

I can also take tokenize($fileHref,'/')[last()] in a variable and use it in
the string operation above. But is there a better way ?

On Aug 24, 2016 12:16 PM, "Mailing Lists Mail daktapaal(_at_)gmail(_dot_)com" <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
> Dear all,
> I have the following two params
> <xsl:param name = “fileHref” select = “
‘P:/developers/perf/bigPayload.xml’ ”/>
> <xsl:param name="outDir" select="'outDir'"/>
>
>   I want OutFileName to be :
‘P:/developers/perf/outDir/bigPayload-Formatted.xml’
> Is there a better way to do this than what I did?
> <xsl:variable name="OutFileName" select=" substring-before($fileHref,
tokenize($fileHref,'/')[last() -1 ] ) || $outDir || '/' ||
substring-before( tokenize($fileHref,'/')[last()] ,'.xml') ||
'-Formatted.xml'"/>
> thanks.
> Dt
>
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