Re: [xsl] How to find out if Xml contains two or more equal element name

something like

<xsl:stylesheet version="2.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
 <xsl:strip-space elements="*"/>
 <xsl:template match="objects">
  <xsl:for-each-group select=".//Nid" group-by=".">
   <xsl:copy-of select="current-group()[2]"/>
  </xsl:for-each-group>
 </xsl:template>
</xsl:stylesheet>


On 7 September 2016 at 10:43, Rahul Singh 
rahulsinghindia15(_at_)gmail(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

> Hi,
>
> I have only one XML. and there <Nid> contains same data like 000817441. I
> want to throw an email for same data.
>
> How to find out if Xml contains two or more equal element name value with
> xsl? But my code is not responding
>
> *Below is XML:*
>
> <?xml version="1.0" encoding="UTF-8"?>
> <objects>
>   <Contact>
>     <Id>003j000001Cj6l8AAB</Id>
>     <Nid>000817441</Nid>
>   </Contact>
>   <Contact>
>     <Id>007j000001Cj6l8AAB</Id>
>     <Nid>000817441</Nid>
>   </Contact>
>   <Contact>
>     <Id>003j700001Cj6l9AAB</Id>
>     <Nid>001191237</Nid>
>   </Contact>
>   <Contact>
>     <Id>003j000801Cj6lAAAR</Id>
>     <Nid>010978087</Nid>
>   </Contact>
>   <Contact>
>     <Id>003j000001Cj9l8AAB</Id>
>     <Nid>000817441</Nid>
>   </Contact>
> </objects>
>
>
> *Below in XSL:*
>
> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/
> 1999/XSL/Transform">
>     <xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
>     <xsl:strip-space elements="*"/>
>     <xsl:template match="objects">
>         <xsl:if
>             test="boolean(//objects/Contact[./Nid &gt;
> preceding-sibling::node() or ./Nid &gt; following-sibling::Nid])">
>             <Nid>
>                 <xsl:value-of select="Nid"/>
>             </Nid>
>         </xsl:if>
>     </xsl:template>
> </xsl:stylesheet>
>
> *Expected output:*
>
> <Nid>000817441</Nid>
>
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