I see that you are dealing with only the names of the grandchildren
of the root. The vollowing has three solutions, one based on the
names (as you have done) and two that are namespace-safe. The latter
two are equivalent, but since the operators "every" and "some" didn't
come to mind for you, I thought I would illustrate both.
The second two work with axes the way you were getting started. But
for the first I think you can rephrase your problem to be not that
all elements have one parent but that there is only one of every
element ... which I think is equivalent given the limited amount of
information regarding your objective.
I hope this helps.
. . . . . . Ken
~/t/ftemp $ cat roger1.xml
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<D1>
<D2/>
<F1/>
</D1>
<D2>
<F2/>
</D2>
</Root>
~/t/ftemp $ cat roger2.xml
<?xml version="1.0" encoding="UTF-8"?>
<Root>
<D1>
<D2/>
<F1/>
</D1>
<D2>
<F2/>
<F1/>
</D2>
</Root>
~/t/ftemp $ xslt2 roger1.xml roger.xsl
true
true
true
~/t/ftemp $ xslt2 roger2.xml roger.xsl
false
false
false
~/t/ftemp $ cat roger.xsl
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:value-of select="
count(/Root/*/*)=count(distinct-values(/Root/*/*/name(.)))"/>
<xsl:text>
</xsl:text>
<xsl:value-of select="
every $elem in /Root/*/* satisfies
not($elem/following::*[not(*)]/node-name(.)=node-name($elem))"/>
<xsl:text>
</xsl:text>
<xsl:value-of select="
not( some $elem in /Root/*/* satisfies
$elem/following::*[not(*)]/node-name(.)=node-name($elem))"/>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
~/t/ftemp $
At 2016-10-16 22:33 +0000, Costello, Roger L. costello(_at_)mitre(_dot_)org
wrote:
Hi Folks,
I am modeling a file system. Below is a sample instance. D1 means
Directory 1, F1 means File 1, etc. The instance says this: the
content of directory 1 is directory 2 and file 1. The content of
directory 2 is file 2. Stated another way, directory 2 and file 1
are contained in directory 1, and file 2 is contained in directory 2.
<Root>
<D1>
<D2/>
<F1/>
</D1>
<D2>
<F2/>
</D2>
</Root>
I want an XPath 2.0 expression which returns true if each object has
one parent. An "object" is a directory or a file. In the example
above each object has one parent, so the XPath should return true.
Below is an illegal file system because F1 has two parents: D1 and D2.
<Root>
<D1>
<D2/>
<F1/>
</D1>
<D2>
<F2/>
<F1/>
</D2>
</Root>
The XPath should return false.
This XPath is almost correct:
for $i in /Root/* return for $j in $i/* return not(name($j) =
$i/following-sibling::*/*/name())
I say it is "almost" correct because it returns multiple Booleans,
not a single Boolean result.
Two Questions:
1. What is the correct XPath expression?
2. Is there a different way to model in XML a file system that would
enable a simple XPath expression?
/Roger
--
Check our site for free XML, XSLT, XSL-FO and UBL developer resources |
Streaming hands-on XSLT/XPath 2 training @US$45: http://goo.gl/Dd9qBK |
Crane Softwrights Ltd. _ _ _ _ _ _ http://www.CraneSoftwrights.com/s/ |
G Ken Holman _ _ _ _ _ _ _ _ _ _
mailto:gkholman(_at_)CraneSoftwrights(_dot_)com |
Google+ blog _ _ _ _ _ http://plus.google.com/+GKenHolman-Crane/posts |
Legal business disclaimers: _ _ http://www.CraneSoftwrights.com/legal |
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--