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Re: [xsl] Assigning new attribute value

2016-12-20 15:07:09
Thanks Michael and Martin. I tried to use the name() earlier, but failed. Mush have been doing it wrong (got a 'not a QName' error). I will try your methods now.
Mark

On 12/20/2016 1:25 PM, Michael Kay mike(_at_)saxonica(_dot_)com wrote:
Try

<Location>
   <xsl:attribute name="{name(@*[1])}" select="$placement-index"/>
</Location>

The [1] isn't necessary if you know there will always be exactly one attribute, 
but it makes it a bit more robust.

Michael Kay
Saxonica

On 20 Dec 2016, at 20:11, Mark Wilson pubs(_at_)knihtisk(_dot_)org 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

I am doing an identity transformation that has presented me with a problem. The 
element <Location> in the original XML must have one and only one of seven 
possible attributes. Whichever attribute is present, I must keep its name but change 
its value. I have created a brute-force template that I assume will work. It 
ascertains the attribute's name and assigns it a new value. This is so ugly I am 
hanging my head in shame. There must be a more elegant method
Mark

xsl:template match="Location">
     <xsl:param name="placement-index"/>
         <Location>
           <xsl:choose>
               <xsl:when test="@minisheet">
                   <xsl:attribute name="minisheet" select="$placement-index"/>
               </xsl:when>
               <xsl:when test="@souvenir-sheet">
                   <xsl:attribute name="souvenir-sheet" 
select="$placement-index"/>
               </xsl:when>
               <xsl:when test="@gutter">
                   <xsl:attribute name="gutter" select="$placement-index"/>
               </xsl:when>
           </xsl:choose>

<!-- There are more attribute names, but you get the idea -->

         </Location>
  </xsl:template>



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