On 09.01.2017 15:25, Steve Wisniewski stevewiz76(_at_)yahoo(_dot_)com wrote:
My question is, how can I sort the groups so that they are sorted in
value order like this:
<table>
<thead>
<tr>
<th>Range</th>
<th>Total Value</th>
</tr>
</thead>
<tbody>
<tr>
<td>3-6</td>
<td>$16,500</td>
</tr>
<tr>
<td>7-10</td>
<td>$7,000</td>
</tr>
<tr>
<td>1-2</td>
<td>$3,000</td>
</tr>
</tbody>
</table>
I understand how to sort within a group but cannot figure out how to
solve this issue.
you can store the result in a variable and then sort it
<xsl:variable name="rows" as="element(tr)*">
<xsl:for-each-group select="location[(xs:integer(class) eq 1) or
(xs:integer(class) eq 2)]" group-by="city">
<tr>
<td>1-2</td>
<td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
</tr>
</xsl:for-each-group>
<xsl:for-each-group select="location[(xs:integer(class) gt 2) and
(xs:integer(class) lt 7)]" group-by="city">
<tr>
<td>3-6</td>
<td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
</tr>
</xsl:for-each-group>
<xsl:for-each-group select="location[xs:integer(class) gt 6]"
group-by="city">
<tr>
<td>7-10</td>
<td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
</tr>
</xsl:for-each-group>
</xsl:variable>
<xsl:perform-sort select="$rows">
<xsl:sort select="xs:decimal(replace(td[2], '[,$]',
''))" order="descending"/>
</xsl:perform-sort>
Having to do the replace after the formatting is probably not the right
approach but you could in the first step only store the number values
and in the second step sort and format if wanted.
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