The difference in return value between fn:boolean('false') and
xs:boolean('false') must be in the top ten of XPath "gotcha's" -- I usually
forget that despite having worked with XPath for more than a decade.
David
On Thu, 2 Mar 2017, Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de wrote:
On 02.03.2017 16:00, Michael Müller-Hillebrand mmh(_at_)docufy(_dot_)de wrote:
<xsl:function name="dy:isFoo" as="xs:boolean">
<xsl:param name="node" as="node()"/>
<xsl:choose>
<xsl:when test="$node[self::bar/@foo = 'x']">
<xsl:value-of select="true()"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="false()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:function>
and changed that to the more elegant:
<xsl:function name="dy:isFoo" as="xs:boolean">
<xsl:param name="node" as="node()"/>
<xsl:sequence select="exists($node[self::bar/@foo = 'x'])"/>
</xsl:function>
BUT then I looked at my old code and said to myself: This could never have
worked?!
Isn't xsl:value-of creating a text node, so in xsl:otherwise it creates
'false'. And if this is cast to boolean as the function requires, we should
get true(), because the string is not empty?
I think the rules lay out that the text node with 'true' or 'false' is
atomized to xs:untypedAtomic 'true' or 'false' and then the conversion to
xs:boolean is defined as a cast based on the XSD schema spec which treats
'true' as the boolean value true and false as the boolean value false. So
what happens in language terms would be
'true' cast as xs:boolean
which gives the boolean value true respectively
'false' cast as xs:boolean
which gives the boolean value false and not
boolean('false')
which would give the boolean value true.
--
David Sewell
Manager of Digital Initiatives
The University of Virginia Press
Email: dsewell(_at_)virginia(_dot_)edu Tel: +1 434 924 9973
Web: http://www.upress.virginia.edu/rotunda
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