Re: [xsl] Passing parameter into tag name

On 12.04.2017 15:06, Steve Wisniewski stevewiz76(_at_)yahoo(_dot_)com wrote:

> <foo>
> <Level>
> <Level_No>1</Level_No>
> </Level>
> <Level>
> <Level_No>2</Level_No>
> </Level>
> <Level>
> <Level_No>3</Level_No>
> </Level>
> <Cost ID='1'>
> <Level_1_Amt>100</Level_1_Amt>
> <Level_2_Amt>200</Level_2_Amt>
> <Level_3_Amt>300</Level_3_Amt>
> </Cost>
> <Cost ID='2'>
> <Level_1_Amt>50</Level_1_Amt>
> <Level_2_Amt>100</Level_2_Amt>
> <Level_3_Amt>150</Level_3_Amt>
> </Cost>
> <Cost ID='3'>
> <Level_1_Amt>175</Level_1_Amt>
> </Cost>
> <Cost ID='4'>
> <Level_3_Amt>400</Level_3_Amt>
> </Cost>
> </foo>
>
> I am trying to sum up the amounts in the following code, but am getting
> a syntactical error about how I am trying to pass the parameter value
> into the tag name:
>
> <xsl:stylesheet version="2.0" xmlns="http://www.w3.org/1999/xhtml";
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:xs="http://www.w3.org/2001/XMLSchema";>
> <xsl:output method="xml" indent="yes"/>
>
> <xsl:template name="buildLevel">
> <xsl:param name="levelNum"/>
> <Level_Amt>
> <xsl:value-of select="sum(/Story/Level_{$levelNum}_Amt)"/>
You need to check the name with e.g.
   sum(/Story/*[local-name() = concat('Level_', $levelNum, '_Amt')])

--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--