Re: [xsl] Remove internal parsing and exclude one child

On 16.05.2017 19:29, Charles O'Connor coconnor(_at_)ariessys(_dot_)com wrote:

> Using XSLT 1.0/Saxon9he
>
> I have this input
>
> <aff id="aff1"><label>1</label>Jet Propulsion Laboratory (JPL), 4800 Oak Grove Dr Pasadena, CA 
> <addr-line><postal-code>91109</postal-code>, <country>USA</country></addr-line></aff>
> <aff id="aff2"><label>2</label>SCRIPPS Institution of Oceanography, 9500 Gilman Drive, <institution>Dept 0230</institution>, 
> <addr-line><city>La Jolla</city>, <state>CA</state> <postal-code>92093-0230</postal-code></addr-line>, 
> <country>USA</country></aff>
>
> And would like to get the same back, without the internal parsing and excluding the 
> contents of <label>, e.g.,
>
> <aff id="aff1">Jet Propulsion Laboratory (JPL), 4800 Oak Grove Dr Pasadena, CA 91109, 
> USA</aff>
> <aff id="aff2">SCRIPPS Institution of Oceanography, 9500 Gilman Drive, Dept 0230, La 
> Jolla, CA 92093-0230, USA</aff>
>
> Using this .xsl
>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>
>   <xsl:template match="node()|@*">
>       <xsl:copy>
>         <xsl:apply-templates select="node()|@*"/>
>       </xsl:copy>
>   </xsl:template>
>   
>   <xsl:template match="//aff">
>       <aff id="{@id}">
>         <xsl:value-of select="."/>
>      </aff>
>   </xsl:template>
>
> </xsl:stylesheet>
>
> I get all the text in <aff>, including the text in <label>.
Use

        <xsl:template match="@* | node()">
                <xsl:copy>
                        <xsl:apply-templates select="@* | node()"/>
                </xsl:copy>
        </xsl:template>
        
        <xsl:template match="aff/label" priority="5"/>
        
        <xsl:template match="aff//*">
                <xsl:apply-templates/>
        </xsl:template>
        


Note that Saxon supports XSLT 2.0 so mentioning XSLT 1.0 in the context 
of Saxon 9 seems an odd requirement but shouldn't matter for that problem.

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