Dear xsl-list,
I know how to accomplish this with XSLT string surgery, but is there an XPath
or XQuery way to calculate the replacement value of the replace() function? The
following (broken) XQuery expresses the general aspiration, although not the
reality:
declare function local:stuff($input) {
let $result := number($input) + 10
return xs:string($result)
};
let $initial := '1 Tim. 4:123'
return replace($initial, '\d+', local:stuff('$0'))
The desired output would be '11 Tim. 14:133', that is, each sequence of digits
would be regarded as a discrete decimal numerical value, captured as the match
with '$0', and passed to the local:stuff() function, where it would be
converted to a number. augmented by 10, converted back to a string (since the
replacement part of the replace() function must be a string), and returned. The
actual output, alas, is 'NaN Tim. NaN:NaN'. Before I give up and do it in XSLT,
I would be grateful for any pointers toward an XPath or XQuery solution.
Best,
David
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