Re: [xsl] Using saxon:parse on processing instructions

That did it, thank you so much Martin for the help.

Cheers,

Spencer

On Mon, Dec 18, 2017 at 2:13 PM, Martin Honnen 
martin(_dot_)honnen(_at_)gmx(_dot_)de <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

> On 18.12.2017 21:18, Spencer Tickner spencertickner(_at_)gmail(_dot_)com 
> wrote:
>
> > Hello and thanks in advance for the help. I'm scratching my head on
> > trying to convert a string of serialized xml in a processing instruction
> > back into XML.
> >
> > I'm restricted to XSLT 2.0 and am using Saxon 9.1. When I treat the
> > simply copy and past the xml into the stylesheet everything works (see
> > variable $s2), but when breaking the string out of the processing
> > instruction the elements remain serialized:
> >
> > input:
> >
> > <?xml version="1.0"?>
> > <root xmlns:bcl="http://bcl";>
> > <?pi a="&lt;bcl:e&gt;Test&lt;/bcl:e&gt;" ?>
> > </root>
> A PI does not contain parsed character data so your data is double escaped.
>
> Does
>
>
>         <xsl:template match="processing-instruction('pi')">
>                 <root xmlns:bcl="http://example.com/bcl";><xsl:value-of
> select="saxon:get-pseudo-attribute('a')" disable-output-escaping="yes"/
> > </root>
>         </xsl:template>
>
>
> work with your version of Saxon?
>
> With Saxon 9.7 PE that gives
>
>         <root xmlns:bcl="http://example.com/bcl";><bcl:e>Test</bcl:e></root
> >
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