Re: [xsl] creating a collection from an archive

Here is part of the solution you what I think. Think I used the various 
namespaces later. This works in the current version of Oxygen. There is an xml 
file in Word that is a manifest of all the files in the zip(Word) and you could 
extract that then use that it get the names of the other files..
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:xs="http://www.w3.org/2001/XMLSchema"; exclude-result-prefixes="xs"
 version="2.0" xmlns:file="java.io.File" 
xmlns:StringUtils="java:org.apache.commons.lang.StringUtils" 
xmlns:class="http://saxon.sf.net/java-type";
 xmlns:ZipFile="java.util.zip.ZipFile" 
xmlns:ZipInputStream="java.util.zip.ZipInputStream">
 <xsl:output indent="yes"/>
 <!-- ========================================= -->
 <xsl:template name="main" match="/">
 <xsl:variable name="doc-content" 
select="doc('jar:file:///G:/Badger/xslt-with-java/XML_Projects.docx!/word/document.xml')"/>
 <xsl:result-document href="document.xml">
 <xsl:copy-of select="$doc-content"/>
 </xsl:result-document>
 </xsl:template>
</xsl:stylesheet>

Terry 

    On ‎Thursday‎, ‎April‎ ‎19‎, ‎2018‎ ‎02‎:‎07‎:‎56‎ ‎PM, Graydon 
graydon(_at_)marost(_dot_)ca 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:  
 
 So I have a Word document, localtest.docx, which is in the 2016 strict
version of the OOXML standard.  As such, it's a zip archive of a bunch
of XML files.  I want to apply XSLT to the XML files.

I could use the arch module and the collection function to write the whole
thing to disk and then load it from disk as a collection before doing whatever
to it and writing it to disk as an archive again, but this seems inefficient.
It would be better to read the archive into an in-memory collection, manipulate
it, and then write that back out as an archive.

I'm using XSLT 3.0 via Saxon 9.8.0.8 in oXygen.

<xsl:variable name="wordArchive" as="document-node()+">
  <xsl:variable name="arch" select="file:read-binary($wordArchiveURI)"/>
  <xsl:variable name="entries" select="arch:entries($arch)"/>
  <xsl:variable name="dirs" select="$entries[ends-with(.,'/')]"/>
  <xsl:sequence select="for $x in ($entries except $dirs)
                      return arch:extract-text($arch,$x) => parse-xml()" />
</xsl:variable>

works, in that I get a sequence of document nodes and those documents have the
expected XML content.

I don't get document nodes with associated document-uri() values or any of the
rest of the archive structure.  Those URIs are in the values returned by
arch:entries but I'm not seeing how I assign a document-uri value to a document
node.  xsl:document doesn't seem to have a facility for assigning a
document-uri value and of course you can't create an attribute whose parent is
a document node even if document-uri was an attribute in the first place.

What I want is a collection where the structure matches the Word archive,
various subdirectories and all, and I can use the doc() function to access
various compontent documents.  I can't shake the feeling that I'm missing
something obvious, but this feeling is no help in discerning what the obvious
thing is!

Thanks!
Graydon

  
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