Re: [xsl] difficulty using xsl:analyze-string

On Wed, 2018-07-18 at 05:34 +0000, Mukul Gandhi 
gandhi(_dot_)mukul(_at_)gmail(_dot_)com
wrote:
> [...]
>               <xsl:analyze-string select="'hello world\nexperimenting
> with
> XSLT\nhow are you'" regex="\n">
Remember that \ isn't special in XML or XPath strings, so your string
contains literal backslashes followed by lower case n. In a regular
expression \ is special however, so to match a literal backslash-n you
want \\n insteaf of \n.

Liam

-- 
Liam Quin, W3C,  http://www.fromoldbooks.org/

Available for stuff.
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--