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Re: [xsl] Efficient XPath 2.0 expression to return each <row> element for which there are other <row> elements having the same navaid?

2018-12-13 13:08:48
Cool--I don't think I realized XQuery 3 had grouping. That's very handy.

Cheers,

E.

--
Eliot Kimber
http://contrext.com
 

On 12/13/18, 12:50 PM, "Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de" 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

    On 13.12.2018 19:40, Eliot Kimber ekimber(_at_)contrext(_dot_)com wrote:
    > If this is a real task support effort and not just a learning exercise 
and you're using Oxygen then I would follow Graydon's lead and use XQuery 3 to 
build a map that can then give you a quick answer.
    
    
    If you move from XPath 2 to XQuery 3 you can as well solve it with grouping
    
       for $row in /airports/row
       group by $id := $row/navaid
       where $row[2]
       return $row
    
    instead of having to build a map.
    
    
    
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