Re: [xsl] bat file creation based on xsl /xml

If I read this right, it looks like you just want to generate a list of the XML 
files in a directory, is that correct?  If you’re in a windows enviroment the 
“dir” command will do what you want.

Michele

From: Rahul Singh rahulsinghindia15(_at_)gmail(_dot_)com 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Monday, January 14, 2019 11:45 AM
To: XSL-List: The Open Forum on XSL 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>; 
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Subject: [xsl] bat file creation based on xsl /xml

Hi,

I want to create .bat file for below logic, i have xml input in 1 directory. 
how to do?:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:xs="http://www.w3.org/2001/XMLSchema"; 
xmlns:fn="http://www.w3.org/2005/xpath-functions"; exclude-result-prefixes="xs 
fn">
            <xsl:output method="text" version="1.0" encoding="UTF-8" 
indent="no"/>
            <xsl:template match="/">
                        <xsl:for-each select="collection('.?select=*.xml')">
                                    <xsl:text>&#10;</xsl:text>
                                                <xsl:value-of 
select="document-uri(.)"/>
                                    </xsl:variable>
                                    </xsl:for-each>
            </xsl:template>
</xsl:stylesheet>

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