On Tue, Mar 05, 2019 at 07:08:02PM -0000, Eliot Kimber
ekimber(_at_)contrext(_dot_)com scripsit:
Given the variable $links that is a sequence of element()s where the elements
could be from different documents, what is the best way to get the set of
unique documents?
I need an XSLT 2 answer but an XSLT 3 answer would also be useful.
I feel like there's an obvious solution I'm overlooking but the only thing I
can think of is to compare the document-uri() values of all the elements:
<xsl:variable name="topicURIs" as="xs:string*"
select="distinct-values(for $e in $links return document-uri(root($e)))"
/>
<xsl:variable name="topics" as="document-node()*"
select="
for $uri in $topicURIs
return root(($links[document-uri(root(.)) eq $uri])[1])
"
/>
This works but seems unnecessarily complicated.
I will admit I'm not sure I follow just what you want, but how would
<xsl:variable name="uniqueTopics" as="document-node()*">
<xsl:for-each-group select="$links" group-by="document-uri(root(.))">
<xsl:sequence select="doc(current-grouping-key())" />
</xsl:for-each-group>
</xsl:variable>
do?
-- Graydon
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