Yes--thanks for catching that--cut and paste error.
Cheers,
E.
--
Eliot Kimber
http://contrext.com
On 4/19/19, 10:10 AM, "Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de"
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
On 19.04.2019 17:02, Eliot Kimber ekimber(_at_)contrext(_dot_)com wrote:
> If you construct map entries for each use and then combine them into a
single map using the "use-first" or "use-any" "duplicates" option then you can
blindly process all the references and let the map-merge process produce a
single list of elements, e.g.;
>
> <xsl:variable name="use-entries" as="map(*)*">
> <xsl:call-template name="find-all-conrefs"/>
> </xsl:variable>
>
> The find-all-conrefs template generates maps, one for each id/element
pair, which you can create with xsl:map or using the literal map constructor:
"map{$key : $value}".
>
> Now make a single map:
>
> <xsl:variable name="use-map" as="map(*)"
> select="map:merge($use-entries, map{ 'duplicates' : 'use-any'}"
> />
>
> And then process the entries to produce the result docs:
>
> <xsl:for-each select="map:keys($use-map)">
> <xsl:variable name="key" select="." as="xs:string"/>
> <xsl:call-template name="make-result-doc">
> <xsl:with-param name="key" as="xs:string" select="$key"/>
> <xsl:with-param name="key" as="element() " select="map:get($use-map,
$key)" as="element() "/>
Isn't that second parameter supposed to be named
<xsl:with-param name="value" as="element() "
select="map:get($use-map, $key)" as="element() "/>
?
> </xsl:call-template>
> </xsl:for-each>
>
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